GATE AE 2026 • Q4 MCQ • 1 Mark

General Aptitude

Analytical & Spatial Aptitude

Subtopic: Deductive Logic & Syllogisms

Question Statement:

How many 3-digit numbers can be formed using three distinct single digit prime numbers?

Options:

  • (A) 64
  • (B) 24
  • (C) 12
  • (D) 4

Official Answer Key:

B

Step-by-Step Solution & Explanation

### **Detailed Step-by-Step Solution (GATE AE 2026 Q.4)** **1. Intuitive Physical Setup & Given Parameters**: We are asked to find the number of 3-digit numbers that can be formed using **three distinct single-digit prime numbers**. **2. Step-by-Step Mathematical Derivation**: 1. **Identify the Single-Digit Prime Numbers**: The single-digit primes (base 10) are: $\mathcal{P} = \{2, 3, 5, 7\}$ There are exactly $n = 4$ such primes: 2, 3, 5, and 7. Note that none of them is 0, so any combination of three distinct digits from this set can form a valid 3-digit number in any position (hundreds, tens, units). 2. **Count the Permutations**: We need to select 3 distinct digits out of the 4 available primes and arrange them in order to form a 3-digit number. The number of such arrangements is given by the permutation formula $P(n, r)$: $P(4, 3) = \frac{4!}{(4-3)!} = \frac{4 \times 3 \times 2 \times 1}{1} = 24$ Alternatively: - Ways to pick the hundreds digit: 4 choices - Ways to pick the tens digit: 3 choices - Ways to pick the units digit: 2 choices $\text{Total 3-digit numbers} = 4 \times 3 \times 2 = 24$ **3. Comprehensive Options & Distractor Analysis**: - **(A) 64**: ❌ **INCORRECT**. Corresponds to allowing repetition ($4^3 = 64$), but the problem explicitly states "distinct". - **(B) 24**: ✅ **CORRECT**. Exactly $P(4, 3) = 4 \times 3 \times 2 = 24$ distinct numbers. - **(C) 12**: ❌ **INCORRECT**. Half the correct value, often from mistakenly dividing by 2. - **(D) 4**: ❌ **INCORRECT**. Represents combinations $\binom{4}{3} = 4$ without permuting the digit positions. **4. Official Master Key & Exam Takeaway**: - **Official Answer Key**: **B** - **Exam Takeaway**: Distinguish between combinations (subsets) and permutations (numbers where digit order matters). Since order signifies place value, multiply combinations by $3! = 6$, yielding $4 \times 6 = 24$.

Practice This in Real CBT Exam Interface

Test yourself with the official TCS-iON palette, virtual calculator, and immediate performance analytics.

Launch CBT Mock Test