GATE AE 2025 • Q4 MCQ • 1 Mark

General Aptitude

Analytical & Spatial Aptitude

Subtopic: Deductive Logic & Syllogisms

Question Statement:

In the given figure, the numbers associated with the rectangle, triangle, and ellipse are 1, 2, and 3, respectively. W hich one among the given options is the most appropriate combination of P, Q, and R ?

Options:

  • (A) P = 6; Q = 5; R = 3
  • (B) P = 5; Q = 6; R = 3
  • (C) P = 3; Q = 6; R = 6
  • (D) P = 5; Q = 3; R = 6 1 2 4 3 P Q R

Official Answer Key:

A

Step-by-Step Solution & Explanation

### **Detailed Step-by-Step Solution (GATE AE 2025 Q.4)** **1. Intuitive Physical Setup & Given Parameters**: The figure depicts overlapping geometric shapes: - Numbers associated with basic shapes: - Rectangle $= 1$ - Triangle $= 2$ - Ellipse $= 3$ The numbers inside each intersection region represent the sum (or product) of the indices of the shapes containing that region. We need to find the combination of values for regions $P$, $Q$, and $R$. **2. Step-by-Step Geometric & Combinatorial Derivation**: 1. **Map Shape Containment for Each Region**: - Region $P$ lies at the common intersection of all three shapes: Rectangle ($1$), Triangle ($2$), and Ellipse ($3$). The combined composite index or sum: $P = 1 + 2 + 3 = 6$ - Region $Q$ lies in the intersection of Triangle ($2$) and Ellipse ($3$): $Q = 2 + 3 = 5$ - Region $R$ lies solely within Ellipse ($3$): $R = 3$ 2. Combining the values: $P = 6, \quad Q = 5, \quad R = 3$ **3. Comprehensive Options & Distractor Analysis**: - **(A) P = 6; Q = 5; R = 3**: ✅ **CORRECT**. Accurately matches the multi-shape membership summation. - **(B) P = 5; Q = 6; R = 3**: ❌ **INCORRECT**. Swaps $P$ and $Q$. - **(C) P = 3; Q = 6; R = 6**: ❌ **INCORRECT**. Incorrect shape assignments. - **(D) P = 5; Q = 3; R = 6**: ❌ **INCORRECT**. Inconsistent with region topology. **4. Official Master Key & Exam Takeaway**: - **Official Answer Key**: **A** - **Exam Takeaway**: Identify the shape boundary set enclosing each designated region and apply the additive combination rule.

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