GATE AE 2025 • Q25 MCQ • 1 Mark

Flight Mechanics & Space Dynamics

Static Stability & Control

Subtopic: Longitudinal Static Stability & Neutral Point

Question Statement:

To achieve longitudinal static stability of a general aviation airplane, which one of the following conditions should be satisfied?

Options:

  • (A) The center of gravity of the airplane should be aft of the neutral point.
  • (B) The center of gravity of the airplane should be forward of the neutral point.
  • (C) The stability coefficient $\frac{\partial C_m}{\partial \alpha}$ ($C_m$ is the airplane pitching moment coefficient and $\alpha$ is the angle of attack) is positive.
  • (D) The static margin is negative.

Official Answer Key:

B

Step-by-Step Solution & Explanation

### **Detailed Step-by-Step Solution (GATE AE 2025 Q.25)** **1. Intuitive Physical Setup & Given Parameters**: - **Physical Concept**: Longitudinal static pitch stability of an aircraft requires that any disturbance in pitch produces a restoring pitching moment to return the aircraft to its equilibrium trim state. - **Governing Variable**: Static margin $K_n = \frac{x_{np} - x_{cg}}{\bar{c}}$, where $x_{np}$ is the longitudinal position of the aerodynamic neutral point and $x_{cg}$ is the center of gravity location. **2. Step-by-Step Mathematical Derivation**: 1. **Pitching Moment Stability Derivative**: For an aircraft disturbed by an incremental angle of attack $\Delta \alpha > 0$, static stability requires a pitch-down (restoring) moment: $C_{m\alpha} = \frac{\partial C_m}{\partial \alpha} < 0$ 2. **Neutral Point and Static Margin Formulation**: The pitching moment about the center of gravity relates to the neutral point by: $C_{m\alpha} = -C_{L\alpha} \left( \frac{x_{np} - x_{cg}}{\bar{c}} \right)$ Since the lift curve slope of the complete aircraft $C_{L\alpha} > 0$: $C_{m\alpha} < 0 \iff x_{np} - x_{cg} > 0 \implies x_{cg} < x_{np}$ Therefore, the center of gravity $x_{cg}$ must lie forward (ahead) of the neutral point $x_{np}$, yielding a positive static margin: $\text{Static Margin} = \frac{x_{np} - x_{cg}}{\bar{c}} > 0$ **3. Comprehensive Options & Distractor Analysis**: - **Option (A)** (aft of neutral point): ❌ **Incorrect**. If $x_{cg} > x_{np}$, the static margin is negative and $C_{m\alpha} > 0$, making the aircraft statically unstable in pitch (pitch-up divergence). - **Option (B)** (forward of neutral point): ✅ **CORRECT**. $x_{cg} < x_{np}$ ensures a positive static margin and a negative restoring pitching moment slope $C_{m\alpha} < 0$. - **Option (C)** ($C_{m\alpha} > 0$): ❌ **Incorrect**. Positive $C_{m\alpha}$ means pitch divergence, not stability. - **Option (D)** (negative static margin): ❌ **Incorrect**. Negative static margin indicates instability. **4. Official Master Key & Exam Takeaway**: - **Official Answer**: **B** - **Exam Rule**: For longitudinal static stability: $x_{cg} < x_{np}$ (cg forward of neutral point), static margin
gt; 0$, and $\frac{\partial C_m}{\partial \alpha} < 0$.

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