GATE AE 2020 • Q53 NAT • 2 Marks

Aerospace Structures

Bending & Shear of Beams

Subtopic: Propped Cantilever Beam Reaction

Question Statement:

As shown in the figure, a beam of length 1 m is rigidly clamped at one end ($x = 0$) and simply supported at the other ($x = 1$ m). Under the action of a uniformly distributed downward load of $w = 10$ N/m, the magnitude of the vertical reaction force (in N) at the simply supported end is _________ (round off to two decimal places).

Official Answer Key:

3.75

Step-by-Step Solution & Explanation

### **Detailed Step-by-Step Solution (GATE AE 2020 Q.53)** **1. Intuitive Physical Setup & Given Parameters**: - Propped cantilever beam of length $L = 1\text{ m}$. - Fixed support at $A$ ($x = 0$), simple roller support at $B$ ($x = L = 1\text{ m}$). - Uniformly distributed load: $w = 10\text{ N/m}$. - Target: Vertical reaction $R_B$ at the simple support. **2. Step-by-Step Structural Mechanics Derivation**: 1. **Statically Indeterminate Beam Analysis (Method of Superposition)**: - Remove the redundant reaction $R_B$ at $B$, leaving a cantilever beam subjected to $w$: Downward tip deflection due to UDL $w$: $\delta_w = \frac{w L^4}{8 EI}$ - Apply upward redundant reaction $R_B$ at tip $B$: Upward tip deflection due to point force $R_B$: $\delta_{R} = \frac{R_B L^3}{3 EI}$ 2. **Compatibility Condition**: Since the simple support at $B$ prevents vertical displacement (zero deflection): $\delta_{net} = \delta_w - \delta_R = 0 \implies \frac{R_B L^3}{3 EI} = \frac{w L^4}{8 EI}$ 3. **Solving for Reaction $R_B$**: $R_B = \frac{3}{8} w L$ 4. **Numerical Substitution**: $R_B = \frac{3}{8} \times (10\text{ N/m}) \times (1\text{ m}) = \frac{30}{8} = 3.75\text{ N}$ The vertical reaction at the simple support is exactly **3.75 N**. **3. Comprehensive Options & Distractor Analysis**: - **Question Type**: Numerical Answer Type (NAT). - **Exact Analytical Result**: **3.75 N** (Acceptable Range: [3.74, 3.76]). **4. Official Master Key & Exam Takeaway**: - **Official Answer**: **3.75** - **Canonical Propped Cantilever Result**: $R_{prop} = \frac{3}{8} w L$; Fixed moment $M_A = \frac{1}{8} w L^2$.

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