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Question 20
GATE AE 2020 • Q20
MCQ • 1 Mark
Flight Mechanics & Space Dynamics
Space Dynamics & Orbital Mechanics
Subtopic: Escape Velocity & Orbit Trajectories
Question Statement:
Burnout velocity of a space vehicle in a circular orbit at an angle $5^\circ$ above the local horizon around earth is 13.5 km/s. The velocity vector orientation indicates the orbit trajectory nature is:
Options:
(A) hyperbolic trajectory
(B) parabolic trajectory
(C) elliptical trajectory
(D) circular trajectory
Step-by-Step Solution & Explanation
### **Detailed Step-by-Step Solution (GATE AE 2020 Q.20)**
**1. Intuitive Physical Setup & Given Parameters**:
- Burnout speed: $V = 13.5\text{ km/s}$.
- Escape speed from low Earth orbit: $v_{esc} = \sqrt{\frac{2\mu}{R_E}} \approx \sqrt{2} \times 7.9\text{ km/s} \approx 11.2\text{ km/s}$.
**2. Step-by-Step Astrodynamics Derivation**:
1. **Specific Orbital Energy ($\mathcal{E}$)**:
$\mathcal{E} = \frac{V^2}{2} - \frac{\mu}{r}$
2. **Comparison with Escape Speed**:
Since $V = 13.5\text{ km/s} > v_{esc} \approx 11.2\text{ km/s}$:
$\mathcal{E} > 0$
3. **Orbit Classification by Specific Energy**:
- $\mathcal{E} < 0$: Elliptic / circular closed orbit (eccentricity $e < 1$).
- $\mathcal{E} = 0$: Parabolic escape trajectory ($e = 1$).
- $\mathcal{E} > 0$: **Hyperbolic escape trajectory** ($e > 1$).
4. Because the burnout velocity exceeds escape velocity, the vehicle escapes Earth's gravitational sphere along a hyperbolic trajectory.
**3. Comprehensive Options & Distractor Analysis**:
- **(A)** hyperbolic trajectory: ✅ **CORRECT**. $V > v_{esc} \implies \mathcal{E} > 0 \implies e > 1$.
- **(B)** parabolic trajectory: ❌ Incorrect. Requires $V = v_{esc}$ exactly.
- **(C)** elliptical trajectory: ❌ Incorrect. Requires $V < v_{esc}$.
- **(D)** circular trajectory: ❌ Incorrect. Requires $V = v_c \approx 7.9\text{ km/s}$ and zero flight path angle.
**4. Official Master Key & Exam Takeaway**:
- **Official Answer**: **A**
- **Exam Rule**: $V > \sqrt{2\mu/r} \implies$ Hyperbolic escape orbit ($e > 1, \mathcal{E} > 0$).
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